Shortest-Job-First (SJR) or non-preemptive sjf cpu scheduling in c

On-campus and online computer science courses to Learn the basic concepts of Computer Science.This tutorial will cover c ,c++, java, data structure and algorithm,computer graphics,microprocessor,analysis of algorithms,Digital Logic Design and Analysis,computer architecture,computer networks,operating system.

code in C:

#include <stdio.h>
int main() 
{
 int i,j,a[10],b[10],temp[10],temp1,avg=0,tt=0,n;
  
 printf("enter the number of Processes:\n");
 scanf("%d",&n); 
 printf("enter arrival time\n");
 for(i=0;i<n;i++)
 scanf("%d",&a[i]); 
 printf("enter burst time\n");
 for(i=0;i<n;i++)
 scanf("%d",&b[i]); 
 for(i=1;i<n;i++)
  for(j=1;j<n;j++)
   if(b[j]>b[j+1])
   {
    temp1=b[j];
    b[j]=b[j+1];
    b[j+1]=temp1;
   } 
 temp[0]=0;
 for(i=0;i<n;i++)
  temp[i+1]=temp[i]+b[i];
 printf("\nGantt Chart\n");
 for(i=0;i<n+1;i++)
  printf("\n%d",temp[i]);
 for(i=1;i<n;i++)
  avg=avg+temp[i]-a[i];
 avg=avg/n;
 printf("\nThe Average WT is %d ms",avg);
  
 for(i=2;i<n+1;i++)
 tt=tt+temp[i]-a[i-1];
 tt+=temp[1];
 tt=tt/n;
 printf("\nThe Average TT is %d ms",tt);
return 0; 
} 

output:-

enter the number of Processes:
5
enter arrival time
0
1
2
3
4
enter burst time
10
3
2
4
5

Gantt Chart

0
10
12
15
19
24
The Average WT is 9 ms
The Average TT is 14 ms
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